如何定制应用程序shell
我想在系统启动时候直接就是我的应用程序画面,请问如何实现?
我是这么做的:
[HKEY_LOCAL_MACHINE\init]
; @CESYSGEN IF CE_MODULES_SHELL
"Launch10"="shell.exe"
; @CESYSGEN ENDIF
IF IMGTINY !
; @CESYSGEN IF CE_MODULES_DEVICE
"Launch20"="device.exe"
; @CESYSGEN ENDIF
; @CESYSGEN IF CE_MODULES_GWES
IF NOGUI !
"Launch30"="gwes.exe"
"Depend30"=hex:14,00
ENDIF
; @CESYSGEN ENDIF
; @CESYSGEN IF CE_MODULES_BTGW
"Launch99"="btgw.exe"
"Depend99"=hex:14,00
; @CESYSGEN ENDIF
ENDIF
IF IMGCELOGENABLE
; At most one CeLog flush app (CeLogFlush, OSCapture) can be used
IF IMGAUTOFLUSH
"Launch05"="CeLogFlush.exe"
ENDIF
IF IMGOSCAPTURE
"Launch05"="OSCapture.exe"
ENDIF
ENDIF
; HIVE BOOT SECTION
; Set Device RootKey and registry enumerator
IF IMGTINY !
; @CESYSGEN IF CE_MODULES_DEVICE
[HKEY_LOCAL_MACHINE\Drivers]
"RootKey"="Drivers\\BuiltIn"