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大家好,下面这个程序可以用串口助手发送十六进制数并在数码管上显示.因为串口通讯软件只能发2位数,所以显示也只能是2位,
请教大家:如和实现三位数字的发送与显示,举例说明:比如我想发送123并在单片机的数码管上显示123,该如何发送与分离数字.
程序如下:
#include
#define uchar unsigned char
#define uint unsigned int
uchar ss,sg;
uchar code table[]={
0xc0,0xf9,0xa4,0xb0,
0x99,0x92,0x82,0xf8,
0x80,0x90,0x88,0x83,
0xc6,0xa1,0x86,0x8e};
void Init_Uart(void);
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void display(uint i)
{
uchar ss,sg;
ss=i/16;
sg=i%16;
P0=table[ss];
P2=0x7f;
delay(2);
P0=table[sg];
P2=0xbf;
delay(2);
}
void main(void)
{
uint i = 0;
Init_Uart();
while(1)
{
if(RI==1)
{
RI = 0;
i = SBUF;
}
else display(i);
}
}
void Init_Uart(void)
{
TMOD = 0x20;
TH1 = 0xFD;
TL1 = 0xFD;
TR1 = 1;
SCON = 0x50;
PCON = 0;
EA = 1;
}
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