C2000 按键中断 抖动

nemo1991

C2000 按键中断 抖动 [复制链接]

新手刚开始学c2000 launchpad，设置了S3-GPIO12的按键中断程序，不过开始运行时发现没有按键也会进入中断。而运行几秒钟后就会变好。请问这是什么问题，程序如下：
中断函数：
interrupt void S3_GetPressed_isr(void)
{
        S3_GetPressed_Flag=1-S3_GetPressed_Flag;

        PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;

}

注意：以下程序 EALLOW/EDIS未写出，实际程序中没问题的。
gpio初始化：
        GpioCtrlRegs.GPAPUD.bit.GPIO12 = 0;
        GpioCtrlRegs.GPAMUX1.bit.GPIO12 = 0;
        GpioCtrlRegs.GPADIR.bit.GPIO12 = 0;  
        GpioCtrlRegs.GPAQSEL1.bit.GPIO12 = 2;
        GpioCtrlRegs.GPACTRL.bit.QUALPRD1 = 0xff;
        GpioIntRegs.GPIOXINT1SEL.bit.GPIOSEL = 12;
连接中断函数：
PieVectTable.XINT1 = &S3_GetPressed_isr;
中断使能：
   XIntruptRegs.XINT1CR.bit.POLARITY = 1;
   XIntruptRegs.XINT1CR.bit.ENABLE = 1;
IER |= M_INT1;
PieCtrlRegs.PIEIER1.bit.INTx4 = 1;

请问问题在哪里？

ltbytyn

初始化时清除中断标志

newofcortexm3

加这些语句：
// Disable CPU interrupts
   DINT;

// Initialize the PIE control registers to their default state.
// The default state is all PIE interrupts disabled and flags
// are cleared.
   InitPieCtrl();

// Disable CPU interrupts and clear all CPU interrupt flags:
   IER = 0x0000;
   IFR = 0x0000;

// Initialize the PIE vector table with pointers to the shell Interrupt
   InitPieVectTable();