launchpad的UART通讯和8路ADC10相互影响，请教各位大神怎么办？

amatelsf · 发表于2012-10-28 20:58

launchpad的UART通讯和8路ADC10相互影响，请教各位大神怎么办？ [复制链接]

赶紧帮帮我吧，好几天啦。。。。以下是我写的launchpad程序，请教给位大神：我想先用P1口的8位ADC10采集完数据后保存起来，然后再用P1.1和P1.2的UART功能把采集到的数据传到PC中，请问我哪儿错了，我一定改！！！！！

#include

#define CPU_F    ((double)1000000)
#define delay_ms(x) __delay_cycles((long)(CPU_F*(double)x/1000.0))//IAR自带的延时
#define delay_us(x) __delay_cycles((long)(CPU_F*(double)x/1000000.0))//IAR自带的延时

#define uchar unsigned char
#define uint unsigned int

int result,AD_result[8];
char result_M[4];
uchar i,u;
double v;

void uart_init()
{
  ADC10CTL0 = 0;//不允许中断
  ADC10CTL1 = 0;
  ADC10AE0  = 0;
  UCA0CTL1|=UCSSEL_2;
UCA0BR0=104;          //波特率为9600
UCA0BR1=0;
UCA0MCTL=UCBRS0;
P1SEL=0;
P1DIR = BIT2;          //P1.2  UART_TX
P1SEL|=BIT1+BIT2;    //将P1.1 P1.2设为第二功能
P1SEL2 = BIT1 + BIT2;
UCA0CTL1&=~UCSWRST;
IE2|=UCA0RXIE;
}

void AD_Init(void)
{
  P1SEL = 0xFF;//将IO选择为AD输入
  P1DIR = 0;
  ADC10CTL0 |= SREF_1+REFON+ADC10IE;//将AD10基准设置为1.5V 开启AD允许中断
  ADC10CTL0 |= ADC10SHT_3+MSC;//打开AD转换，过采样率设置为64个采样周期
  ADC10CTL1 |= ADC10SSEL_3+SHS_0;//选择250K的采样时钟，用ADC10SC触发采集
  ADC10CTL1 |= CONSEQ_1+INCH_7;//连续采样模式，从通道0~7
  ADC10CTL0 |= ADC10ON;
  ADC10AE0  |= 0xFB;
  ADC10CTL0 |= ADC10SC+ENC;
}

void send(uchar c)
{
UCA0TXBUF=c;
while(!(IFG2&UCA0TXIFG));
IFG2&=~UCA0TXIFG;
}

void main()
{
WDTCTL=WDTPW+WDTHOLD;
DCOCTL=CALDCO_1MHZ;    //将DCO设为1mhz
BCSCTL1=CALBC1_1MHZ;
for(u=0;u<8;u++)
{
   AD_result=0;
}
uart_init();
send('B');
send('e');
send('g');
send('i');
send('n');
send(':');
while(1)
{
//    send('A');
   AD_Init();
   _EINT();
   delay_ms(50);
   ADC10CTL0 |= ENC+ADC10SC;
   delay_ms(50);
   uart_init();
   send(0x31);
   send(AD_result[0]);
   send(AD_result[1]);
   send(AD_result[6]);
   delay_ms(500);
}
}
#pragma vector=ADC10_VECTOR
__interrupt void ADC10_ISR(void)
{
  AD_result=ADC10MEM;
  u--;
  if(u>8)
  {
u=7;
  }
}