TI MSP430 中断

jackping025 · 发表于2008-12-20 04:16

TI MSP430 中断 [复制链接]

我刚有了一个面试，给我留了个作业。哪位能帮帮我？我的工作就有希望了
写小段程序 TI MSP430Fxxx
1) 用中断控制
2) 在P1.0产生一个连续的 1KHz 变占空比的输出
3) 占空比由P1.1 P1.2 P1.3 控制如下
  P1.1    P1.2    P1.3       占空比(on-off)
  0       1       1             90-10
  1       0       1             70 - 30
  0       0       1             50 - 50
  1       1       0             30 - 70
  0       1       0             10 - 90

napolun · 发表于2008-12-20 07:48

ding

hero362631780 · 发表于2008-12-20 07:48

ding

taotao39329112 · 发表于2008-12-21 07:11

我自己写了一个，找错加分
#include "MSP430x22x4.h"

#define MAXSTEP 1000-1 // clk 1mHz /1k freq required=1000 step
#define DUTYCYCLE10 100 //dutycycle 10
#define DUTYCYCLE30 300 //dutycycle 30
#define DUTYCYCLE50 500 //dutycycle 50
#define DUTYCYCLE70 700 //dutycycle 70
#define DUTYCYCLE90 900 //dutycycle 90

#define STATUS1 0xC //input combination
#define STATUS2 0xA
#define STATUS3 0x8
#define STATUS4 0x6
#define STATUS5 0x4

#define ENABLE1 0xC //interrupt enable setting
#define ENABLE2 0xA
#define ENABLE3 0x8
#define ENABLE4 0x6
#define ENABLE5 0x4

unsigned int dutycyle = DUTYCYCLE10;
unsigned int start = DUTYCYCLE10;
unsigned int end = DUTYCYCLE30;

void init_port1(void)
{
P1DIR = 0x1;               //P1.0 ouput
P1SEL = 0x1;             //timer A output P1.0
P1IE = 0xE; //Enable interrupt
P1IFG = 0x0; //Clear flag

// POR input status detection in order to set Interrupt edge
switch(P1IN&0xOE)
{
   case STATUS1: //Input P1.1, P1.2 and P1.3 STATUS
   start = DUTYCYCLE90;//set starting dutycle
   end = DUTYCYCLE10;//set ending dutycle
   P1IES = ENABLE1;//reset interrupt ENABLE
   break;
   case STATUS2:
   start = DUTYCYCLE70;//set starting dutycle
   end = DUTYCYCLE30;//set ending dutycle
   P1IES = ENABLE2;//reset interrupt ENABLE
   break;
   case STATUS3:
   start = DUTYCYCLE50;//set starting dutycle
   end = DUTYCYCLE50;//set ending dutycle
   P1IES = ENABLE3;//reset interrupt ENABLE
   break;
   case STATUS4:
   start = DUTYCYCLE30;//set starting dutycle
   end = DUTYCYCLE70; //set ending dutycle
   P1IES = ENABLE4;//reset interrupt ENABLE
   break;
   case STATUS5:
   start = DUTYCYCLE10;//set starting dutycle
   end = DUTYCYCLE90; //set ending dutycle
   P1IES = ENABLE5;//reset interrupt ENABLE
   break;
   default:
   start = DUTYCYCLE90;//set starting dutycle
   end = DUTYCYCLE10; //set ending dutycle
   P1IES = ENABLE1;//reset interrupt ENABLE

   break;
}
}

void main (void)
{
WDTCTL = WDTPW + WDTHOLD;          //Stop watch dog

    BCSCTL1 = CALBC1_1MHZ;          //(0x10FF)
DCOCTL = CALDCO_1MHZ

init_port1();

TACTL = TASSEL1 + TACLR; // SMCLK, clear
TACTL = MC_1+CNTL_0+TACLGRP_0; //up,16 bits
TACCTL0 = CCIE; //timer seting
TACCTL1 = OUTMOD_7+CLLD_1; //mode 7
    TACCR0 = MAXSTEP;             //PWM freq
    TACCR1 = DUTYCYCLE10; //duty cycle

    _EINT();
LPM0;
}

#pragma vector=TIMERA0_VECTOR
__interrupt void TimerA0_ISR(void)
{
  if (end>=start)
{
   if(dutycyle>=start)&(dutycyle    else dutycyle= start;
}
else
{
if(dutycyle>=end)&(dutycyle else dutycyle= start;
}
TACCR1 = dutycyle;
}

#pragma vector=P1_VECTOR
__interrupt void P1_ISR(void)
{
P1IFG=0; //clear flag P1IFG
    switch(P1IN&0xOE)// Asuming there might be some jitter { //So, I don't use the P1IFG  to determion the state,
   case STATUS1: //Input P1.1, P1.2 and P1.3 STATUS
   start = DUTYCYCLE90; //set starting dutycle
   end    = DUTYCYCLE10; //set ending dutycle
   P1IES = ENABLE1; //reset interrupt ENABLE
   break;
   case STATUS2:
   start = DUTYCYCLE70; //set starting dutycle
   end    = DUTYCYCLE30; //set ending dutycle
   P1IES = ENABLE2; //reset interrupt ENABLE
   break;
   case STATUS3:
   start = DUTYCYCLE50; //set starting dutycle
   end    = DUTYCYCLE50; //set ending dutycle
   P1IES = ENABLE3; //reset interrupt ENABLE
   break;
   case STATUS4:
   start = DUTYCYCLE30; //set starting dutycle
   end    = DUTYCYCLE70; //set ending dutycle
   P1IES = ENABLE4; //reset interrupt ENABLE
   break;
   case STATUS5:
   start = DUTYCYCLE10; //set starting dutycle
   end    = DUTYCYCLE90; //set ending dutycle
   P1IES = ENABLE5; //reset interrupt ENABLE
   break;
   default:
   break;
   }
}

snwhtyvi · 发表于2008-12-21 10:19

代码的架子没错，而且这个是最基本的东西，建议你自己做然后把遇到的问题贴上来．这样才会有提高噢．

jfive · 发表于2008-12-21 10:55

我的问题：中断服务程序中，设下次端口触发中断的上升沿或下降沿时，根据什么（因为端口高低已经翻转）
选择1.当前端口的状态
选择2.上次中断留下的标志
如果2，端口有抖动怎么办

merryimage · 发表于2008-12-21 14:51

1) 用中断控制
2) 在P1.0产生一个连续的 1KHz 变占空比的输出
3) 占空比由P1.1 P1.2 P1.3 控制如下
  P1.1    P1.2    P1.3       占空比(on-off)
  0       1       1             90-10
  1       0       1             70 - 30
  0       0       1             50 - 50
  1       1       0             30 - 70
  0       1       0             10 - 90

/////////////////////////////////////////////

看了一下你的题目没看你的代码

1KHZ
占空比精度要到1/10

那先把定时器搞到10KHZ

每一次定时刚刚好是1/10，然后10次，刚刚好是1KHZ

爽。。。

把控制IO读进来

然后，丢到定时器处理的状态机（自己建一个状态机）上

定时反转

真帅。。。

代码行应该只有LZ给的代码的1/2

嘿嘿，而且还足够帅