【DigiKey创意大赛】密码锁+矩阵键盘的读取python实现
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首先我的想法是充分发挥手中的可以直接上手,最简单的方式使用的,最小方案吧。于是我决定还是弄个矩阵键盘的python程序控制看看。
# Include the library files
import RPi.GPIO as GPIO
from time import sleep
# Enter column pins
C1 = 5
C2 = 6
C3 = 13
C4 = 19
# Enter row pins
R1 = 12
R2 = 16
R3 = 20
R4 = 21
keypadPressed = -1
# Enter your PIN
secretCode = "1111"
input = ""
# Setup GPIO
GPIO.setwarnings(False)
GPIO.setmode(GPIO.BCM)
# Set column pins as output pins
GPIO.setup(C1, GPIO.OUT)
GPIO.setup(C2, GPIO.OUT)
GPIO.setup(C3, GPIO.OUT)
GPIO.setup(C4, GPIO.OUT)
# Set row pins as input pins
GPIO.setup(R1, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
GPIO.setup(R2, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
GPIO.setup(R3, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
GPIO.setup(R4, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
# This callback registers the key that was pressed
# if no other key is currently pressed
def keypadCallback(channel):
global keypadPressed
if keypadPressed == -1:
keypadPressed = channel
# Detect the rising edges
GPIO.add_event_detect(R1, GPIO.RISING, callback=keypadCallback)
GPIO.add_event_detect(R2, GPIO.RISING, callback=keypadCallback)
GPIO.add_event_detect(R3, GPIO.RISING, callback=keypadCallback)
GPIO.add_event_detect(R4, GPIO.RISING, callback=keypadCallback)
# Sets all rows to a specific state.
def setAllRows(state):
GPIO.output(C1, state)
GPIO.output(C2, state)
GPIO.output(C3, state)
GPIO.output(C4, state)
# Check or clear PIN
def commands():
global input
pressed = False
GPIO.output(C1, GPIO.HIGH)
# Clear PIN
if (GPIO.input(R1) == 1):
print("Input reset!");
sleep(1)
pressed = True
GPIO.output(C1, GPIO.HIGH)
# Check PIN
if (not pressed and GPIO.input(R2) == 1):
if input == secretCode:
print("Code correct!")
else:
print("Incorrect code!")
pressed = True
GPIO.output(C1, GPIO.LOW)
if pressed:
input = ""
return pressed
# reads the columns and appends the value, that corresponds
# to the button, to a variable
def read(column, characters):
global input
GPIO.output(column, GPIO.HIGH)
if(GPIO.input(R1) == 1):
input = input + characters[0]
print(input)
if(GPIO.input(R2) == 1):
input = input + characters[1]
print(input)
if(GPIO.input(R3) == 1):
input = input + characters[2]
print(input)
if(GPIO.input(R4) == 1):
input = input + characters[3]
print(input)
GPIO.output(column, GPIO.LOW)
try:
while True:
input = input("Enter your PIN: ")
# If a button was previously pressed,
# check, whether the user has released it yet
if keypadPressed != -1:
setAllRows(GPIO.HIGH)
if GPIO.input(keypadPressed) == 0:
keypadPressed = -1
else:
sleep(0.1)
# Otherwise, just read the input
else:
if not commands():
read(C1, ["D","C","B","A"])
read(C2, ["#","9","6","3"])
read(C3, ["0","8","5","2"])
read(C4, ["*","7","4","1"])
sleep(0.1)
else:
sleep(0.1)
except KeyboardInterrupt:
print("Stopped!")
How to make a door lock security system with a Raspberry Pi board _ Raspberry Pi Projects
这个是参考视频
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