msp430ADC采样问题

ts19891230

msp430ADC采样问题 [复制链接]

我想用149芯片的P6口进行采样，现在不知道怎么回事只能让P6.0口采样，怎么让P6.1口采样，怎么设置，我弄了一上午了

wstt

//                 MSP430F149
//            -----------------
//           |                 |
//   Vin0 -->|P6.0/A0          |
//   Vin1 -->|P6.1/A1          |
//   Vin2 -->|P6.2/A2          |
//   Vin3 -->|P6.3/A3          |
//           |                 |

wstt

1. #include <msp430x14x.h>
   
   #define Num_of_Results 8
   
   static unsigned int A0results[Num_of_Results]; // These need to be global in
   static unsigned int A1results[Num_of_Results]; // this example. Otherwise, the
   static unsigned int A2results[Num_of_Results]; // compiler removes them because
   static unsigned int A3results[Num_of_Results]; // they are not used
   
   void main(void)
   {
   WDTCTL = WDTPW+WDTHOLD; // Stop watchdog timer
   P6SEL = 0x0F; // Enable A/D channel inputs
   ADC12CTL0 = ADC12ON+MSC+SHT0_8; // Turn on ADC12, extend sampling time
   // to avoid overflow of results
   ADC12CTL1 = SHP+CONSEQ_3; // Use sampling timer, repeated sequence
   ADC12MCTL0 = INCH_0; // ref+=AVcc, channel = A0
   ADC12MCTL1 = INCH_1; // ref+=AVcc, channel = A1
   ADC12MCTL2 = INCH_2; // ref+=AVcc, channel = A2
   ADC12MCTL3 = INCH_3+EOS; // ref+=AVcc, channel = A3, end seq.
   ADC12IE = 0x08; // Enable ADC12IFG.3
   ADC12CTL0 |= ENC; // Enable conversions
   ADC12CTL0 |= ADC12SC; // Start conversion
   _BIS_SR(LPM0_bits + GIE); // Enter LPM0, Enable interrupts
   }
   
   #pragma vector=ADC12_VECTOR
   __interrupt void ADC12ISR (void)
   {
   static unsigned int index = 0;
   
   A0results[index] = ADC12MEM0; // Move A0 results, IFG is cleared
   A1results[index] = ADC12MEM1; // Move A1 results, IFG is cleared
   A2results[index] = ADC12MEM2; // Move A2 results, IFG is cleared
   A3results[index] = ADC12MEM3; // Move A3 results, IFG is cleared
   index = (index+1)%Num_of_Results; // Increment results index, modulo; Set Breakpoint here
   }
   

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